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| #include <stdio.h> #include <stdint.h> #define DELTA 0x9e3779b9 #define MX (((z>>5^y<<2) + (y>>3^z<<4)) ^ ((sum^y) + (key[(p&3)^e] ^ z)))
void btea(uint32_t *v, int n, uint32_t const key[4]) { uint32_t y, z, sum; unsigned p, rounds, e; if (n > 1) { rounds = 6 + 52/n; sum = 0; z = v[n-1]; do { sum += DELTA; e = (sum >> 2) & 3; for (p=0; p<n-1; p++) { y = v[p+1]; z = v[p] += MX; } y = v[0]; z = v[n-1] += MX; } while (--rounds); } else if (n < -1) { n = -n; rounds = 6 + 52/n; sum = rounds*DELTA; y = v[0]; do { e = (sum >> 2) & 3; for (p=n-1; p>0; p--) { z = v[p-1]; y = v[p] -= MX; } z = v[n-1]; y = v[0] -= MX; sum -= DELTA; } while (--rounds); } }
int main() { uint32_t v[4]= {0x73647979,0x726b6f5f,0x646f675f,0x0}; uint32_t const k[4]= {0X95C4C,0X871D,0X1A7B7,0X12C7C7}; int n= 2; printf("加密前原始数据:%s\n",(char*)v); btea(v, n, k); printf("加密后的数据:%u %u %u\n",v[0],v[1],v[3]); btea(v, -n, k); printf("解密后的数据:%s\n",(char*)v); return 0; }
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